Penjelasan dengan langkah-langkah:
BAGIAN A
L = π × r²
L = 22/7 × 35 × 35
L = 22 × 5 × 35
L = 110 × 35
L = 3.850 Cm²
BAGIAN B
L = π × r²
L = 22/7 × 7 × 7
L = 22 × 7
L = 154 Cm²
》Penyelesaian
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Luas Lingkaran (a)
Jari jari = 35 cm
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[tex] \tt \: = \pi \times {r}^{2} [/tex]
[tex] \tt = \frac{22}{7} \times {35}^{2} [/tex]
[tex] \tt = \frac{22}{ { \not7}^{1} } \times { \not1.225}^{175 } [/tex]
[tex] \tt = 22 \times 175[/tex]
[tex] \green{ \boxed{\tt = 3.850 \: {cm}^{2} }}[/tex]
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Luas Lingkaran (b)
Diameter = 14 cm
Jari = D : 2 = 14 : 2 = 7 cm
~~
[tex] \tt =\pi \times {r}^{2} [/tex]
[tex] \tt = \frac{22}{7} \times {7}^{2} [/tex]
[tex] \tt = \frac{22}{ { \not7}^{1} } \times { \not49}^{7} [/tex]
[tex] \tt = 22 \times 7[/tex]
[tex] \blue {\boxed{\tt = 154 \: {cm}^{2}}} [/tex]
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